Remedial matematika bu puji

1. x + 2 y =-4
   2x + y = 1                                                                          x=(-4) -2 y 
                                                                                               x=(- 4) - 2 (- 3)
                                                                                               x=( - 4) + 6
                                                                                               x = 2
                                                                                               hp=(2,-3)
 subsitusi
2x + y = 1
2 (-4) -2 y + y = 1
(-8) - 4 y + y = 1
(- 8) -3 y = 1
- 3 y = 1 + 8
y = 9/3
y = - 3

eliminasi
x + 2 y = - 4
2 x + y = 1
                                                                              2 x + 4 y  = - 8
                                                                              2 x + y = 1
                                                                          ____________________ -
                                                                                   3 y = - 9
                                                                                      y = - 9/3
                                                                                      y = - 3
2 x + y = 1
2 x + (-3) =1
2 x . 3 = 1
    2 x = 1 + 3
    x = 4 / 2
    x = 2                                                                   hp= ( 2 ,- 3 )